Rumus ABC Dari 3x² - 12x + 2 = 0
Jawaban:
PK =
a = 3
b = -12
c = 2
3x² - 12x + 2 = 0
x_{1,2} = -(b ± √b² - 4ac)/2a
x_{1,2} = -(-12 ± √(-12)² - 4(3)(2)) / 2(3)
x_{1,2} = -(-12 ± √144 - 24) / 6
x_{1,2} = (12 ± √120)/6
x_{1,2} = (12 ± √30√4)/6
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Jawaban:
PK =
a = 3
b = -12
c = 2
3x² - 12x + 2 = 0
x_{1,2} = -(b ± √b² - 4ac)/2a
x_{1,2} = -(-12 ± √(-12)² - 4(3)(2)) / 2(3)
x_{1,2} = -(-12 ± √144 - 24) / 6
x_{1,2} = (12 ± √120)/6
x_{1,2} = (12 ± √30√4)/6